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Platon Sudoku · Sudoku Study

XY-Wing · Step-by-step example

A two-candidate pivot {X,Y} sees two wings {X,Z} and {Y,Z}. The wings may connect through a box, a row, or a column. Remove the shared third digit from a candidate that sees both wings.

This course is adapted from Platon Sudoku App. Read the complete example here, then continue learning and practising in the app.

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Recognize the pattern

A two-candidate pivot {X,Y} sees two wings {X,Z} and {Y,Z}. The wings may connect through a box, a row, or a column.

How to find it

Find a two-candidate pivot, then two other pairs that each share one different pivot digit and the same third digit.

What it allows

Remove the shared third digit from a candidate that sees both wings.

Avoid the mix-up

The pivot itself must have exactly two candidates. The target must see both wings; seeing only the pivot is insufficient.

Step-by-step example · Row and column

This example starts from a saved intermediate position. Its candidates include earlier logical eliminations; they are not fresh automatic notes.

Blue: evidence. Green: conclusion. Crossed-out digits: eliminated candidates. R1C1 means row 1, column 1.

Step 1 · Find the pivot and wings

R3C4 is the pivot with candidates 2, 6. It sees the two wings: R3C9 with 1, 6, and R9C4 with 1, 2.

R3C4 is the pivot with candidates 2, 6. It sees the two wings: R3C9 with 1, 6, and R9C4 with 1, 2.
R3C4 is the pivot with candidates 2, 6. It sees the two wings: R3C9 with 1, 6, and R9C4 with 1, 2.
Step 2 · Find the shared target

Both wings contain 1. Every target (R9C9=1) sees both wings, so it is their shared target for candidate 1.

Both wings contain 1. Every target (R9C9=1) sees both wings, so it is their shared target for candidate 1.
Both wings contain 1. Every target (R9C9=1) sees both wings, so it is their shared target for candidate 1.
Step 3 · Case 1: R3C4 is 2

If R3C4=2, R9C4 cannot be 2 and must be 1.

If R3C4=2, R9C4 cannot be 2 and must be 1.
If R3C4=2, R9C4 cannot be 2 and must be 1.
Step 4 · Case 1: remove target 1

Every target (R9C9=1) sees R9C4, which is 1 in this case. The target therefore cannot be 1.

Every target (R9C9=1) sees R9C4, which is 1 in this case. The target therefore cannot be 1.
Every target (R9C9=1) sees R9C4, which is 1 in this case. The target therefore cannot be 1.
Step 5 · Case 2: R3C4 is 6

If R3C4=6, R3C9 cannot be 6 and must be 1.

If R3C4=6, R3C9 cannot be 6 and must be 1.
If R3C4=6, R3C9 cannot be 6 and must be 1.
Step 6 · Case 2: remove target 1

Every target (R9C9=1) sees R3C9, which is 1 in this case. The target therefore cannot be 1.

Every target (R9C9=1) sees R3C9, which is 1 in this case. The target therefore cannot be 1.
Every target (R9C9=1) sees R3C9, which is 1 in this case. The target therefore cannot be 1.
Step 7 · Combine the two cases

The pivot can only be 2, 6. In either case one wing is 1, so remove R9C9=1.

The pivot can only be 2, 6. In either case one wing is 1, so remove R9C9=1.
The pivot can only be 2, 6. In either case one wing is 1, so remove R9C9=1.

What it allows

The pivot can only be 2, 6. In either case one wing is 1, so remove R9C9=1.

XY-Wing · Remove the shared third digit from a candidate that sees both wings.
XY-Wing · Remove the shared third digit from a candidate that sees both wings.

Practice

This course is adapted from Platon Sudoku App. Read the complete example here, then continue learning and practising in the app.

View on Google Play